Question

#9a: ∠ljk and ∠mjl are
#9b: m∠ljk =
your answer
#10a: ∠acd and ∠bce are

Explanation:

Step1: Identify angle - type relationship

Since $\angle MJL$ and $\angle LJK$ together form $\angle MJK$ and $\angle MJL = 68^{\circ}$ and $\angle MJK$ is a right - angle ($90^{\circ}$), $\angle LJK$ and $\angle MJL$ are complementary angles.

Step2: Calculate $\angle LJK$

We know that if two angles $\alpha$ and $\beta$ are complementary, $\alpha+\beta = 90^{\circ}$. Let $\alpha=\angle LJK$ and $\beta = \angle MJL=68^{\circ}$. Then $\angle LJK=90^{\circ}-\angle MJL$.
$m\angle LJK=90 - 68$

Answer:

#9a: Complementary angles
#9b: 22