Question

9x = 45; 32 = 8a; 3x = 36; \frac{x}{5} = 2; 21 = \frac{x}{3}; 8b = 56

Explanation:

Step1: Solve $9x=45$

Divide both sides by 9:
$\frac{9x}{9}=\frac{45}{9}$
$x=5$

Step2: Solve $3z=36$

Divide both sides by 3:
$\frac{3z}{3}=\frac{36}{3}$
$z=12$

Step3: Solve $\frac{x}{3}=21$

Multiply both sides by 3:
$\frac{x}{3} \times 3=21 \times 3$
$x=63$

Step4: Solve $32=8a$

Divide both sides by 8:
$\frac{32}{8}=\frac{8a}{8}$
$a=4$

Step5: Solve $\frac{x}{5}=2$

Multiply both sides by 5:
$\frac{x}{5} \times 5=2 \times 5$
$x=10$

Step6: Solve $8b=56$

Divide both sides by 8:
$\frac{8b}{8}=\frac{56}{8}$
$b=7$

Answer:

$x=5$; $z=12$; $x=63$; $a=4$; $x=10$; $b=7$