Question

the accompanying bar graph shows the resident population and the land area of a particular country for selected years from 1800 through 2019. use the information to complete parts (a) and (b) below.
a. find the population density of the country, to the nearest tenth, in 1900 and in 2019
b. find the percent increase in population density, to the nearest tenth of a percent, from 1900 to 2019
click here to view a bar graph showing resident population and the land area of a particular country for selected years from 1800 through 2019.
a. the population density, to the nearest tenth, in 1900 was
(round to the nearest tenth as needed.)
figure
1800 \t5,308,483 \t864,746
1900 \t71,026,752 \t2,966,711
1940 \t131,669,275 \t2,971,128
1980 \t226,545,805 \t3,539,289
2019 \t284,364,791 \t3,685,096

Explanation:

Step1: Recall population density formula

Population density is calculated as the number of people divided by the land area. The formula is \( \text{Population Density} = \frac{\text{Population}}{\text{Land Area}} \).

Step2: Identify 1900's population and land area

From the table, in 1900, the population is \( 71,026,752 \) and the land area is \( 2,966,711 \).

Step3: Calculate 1900's population density

Substitute the values into the formula: \( \text{Population Density} = \frac{71026752}{2966711} \).
Using a calculator, \( \frac{71026752}{2966711} \approx 23.9 \) (rounded to the nearest tenth).

Answer:

23.9