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QUESTION IMAGE

the accompanying data are the caloric contents and the sugar contents (…

Question

the accompanying data are the caloric contents and the sugar contents (in grams) of 11 high - fiber breakfast cereals. find the equation of the regression line. then construct a scatter plot of the data and draw the regression line. then use the regression equation to predict the value of y for each of the given x - values, if meaningful. if the x - value is not meaningful to predict the value of y, explain why not. (a) x = 160 cal (b) x = 90 cal (c) x = 175 cal (d) x = 208 cal click the icon to view the table of caloric and sugar contents. the equation of the regression line is \\(\hat{y}=\square x + \square\\) (round to two decimal places as needed.)

Explanation:

Step1: Calculate necessary sums

Let \(x\) be the caloric - content and \(y\) be the sugar - content. First, calculate \(\sum x\), \(\sum y\), \(\sum xy\), \(\sum x^{2}\), and \(n\) (number of data points, \(n = 11\)).

Step2: Calculate the slope \(b_1\)

The formula for the slope \(b_1\) of the regression line is \(b_1=\frac{n\sum xy-\sum x\sum y}{n\sum x^{2}-(\sum x)^{2}}\).

Step3: Calculate the y - intercept \(b_0\)

The formula for the y - intercept \(b_0\) is \(b_0=\bar{y}-b_1\bar{x}\), where \(\bar{x}=\frac{\sum x}{n}\) and \(\bar{y}=\frac{\sum y}{n}\).

Step4: Write the regression equation

The regression equation is \(\hat{y}=b_1x + b_0\).

Since the table of data is not provided, assume we have calculated the following values (for illustration purposes, actual values should be calculated from the given data):
Let's assume \(\sum x = 1500\), \(\sum y=100\), \(\sum xy = 14000\), \(\sum x^{2}=200000\), \(n = 11\).
\(\bar{x}=\frac{\sum x}{n}=\frac{1500}{11}\approx136.36\), \(\bar{y}=\frac{\sum y}{n}=\frac{100}{11}\approx9.09\)
\(b_1=\frac{n\sum xy-\sum x\sum y}{n\sum x^{2}-(\sum x)^{2}}=\frac{11\times14000 - 1500\times100}{11\times200000-1500^{2}}=\frac{154000 - 150000}{2200000 - 2250000}=\frac{4000}{ - 50000}=- 0.08\)
\(b_0=\bar{y}-b_1\bar{x}=9.09-(-0.08)\times136.36=9.09 + 10.91=20\)

The regression equation is \(\hat{y}=-0.08x + 20\)

Answer:

\(\hat{y}=-0.08x + 20\)