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according to the vertical angle theorem, vertical angles are congruent.…

Question

according to the vertical angle theorem, vertical angles are congruent. which of the following statements can be used to prove that ∠aob≅∠cod? draw show your work here o m∠aob = 180° o m∠aoc + m∠aod + m∠bod + m∠boc = 360° o m∠aob + m∠boc = 180° and m∠cod + m∠boc = 180° o m∠aod = m∠boc

Explanation:

Step1: Recall vertical - angle property

Vertical angles are formed when two lines intersect. $\angle AOB$ and $\angle COD$ are vertical angles. If we can show that they are supplementary to the same angle, it proves their congruence.

Step2: Analyze each option

  • Option 1: $m\angle AOB = 180^{\circ}$ only gives the measure of $\angle AOB$ alone, not related to $\angle COD$.
  • Option 2: $m\angle AOC + m\angle AOD + m\angle BOD + m\angle BOC=360^{\circ}$ is about the sum of all angles around the intersection point, not directly related to proving $\angle AOB\cong\angle COD$.
  • Option 3: If $m\angle AOB + m\angle BOC = 180^{\circ}$ and $m\angle COD + m\angle BOC = 180^{\circ}$, then by the subtraction property of equality, we can subtract $m\angle BOC$ from both equations. So $m\angle AOB=m\angle COD$, which means $\angle AOB\cong\angle COD$.
  • Option 4: $m\angle AOD = m\angle BOC$ is about another pair of vertical angles, not helpful for proving $\angle AOB\cong\angle COD$.

Answer:

$m\angle AOB + m\angle BOC = 180^{\circ}$ and $m\angle COD + m\angle BOC = 180^{\circ}$