Question

alex has 20 apples. he wants to distribute the apples among his 4 friends. which measure of center should he use so that each friend gets a fair share of apples? mode median mean range what is 3,795 + 2,814? a 5,509 b 5,609 c 6,609 d 6,619 which is true? 6x2 = 8+2 3x6 = 9+2 6x4 = 18+6 3x7 = 9+1

Explanation:

First Question:

To distribute 20 apples fairly among 4 friends, we need to find the average number of apples per friend. The mean is the measure of center that represents the average value. The mode is the most frequently - occurring value, the median is the middle value when data is ordered, and the range is the difference between the maximum and minimum values. None of these (mode, median, range) are relevant for fair distribution.

Second Question:

Step1: Add the numbers

$3795+2814=(3000 + 700+90 + 5)+(2000+800 + 10+4)$
$=(3000+2000)+(700 + 800)+(90+10)+(5 + 4)$
$=5000+1500+100 + 9$
$=6609$

Third Question:

Step1: Evaluate left - hand side and right - hand side of each option

Option 1:

Left - hand side: $6\times2 = 12$, Right - hand side: $8 + 2=10$, $12
eq10$

Option 2:

Left - hand side: $3\times6=18$, Right - hand side: $9 + 2 = 11$, $18
eq11$

Option 3:

Left - hand side: $6\times4 = 24$, Right - hand side: $18+6=24$, $24 = 24$

Option 4:

Left - hand side: $3\times7=21$, Right - hand side: $9 + 1=10$, $21
eq10$

Answer:

1. mean
2. C. 6,609
3. $6\times4=18 + 6$