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algebra 2 © 2023 kuta software llc dividing polynomials divide. 1) $(n^…

Question

algebra 2
© 2023 kuta software llc
dividing polynomials
divide.

  1. $(n^3 - 10n^2 + 26n - 8) ÷ (n - 4)$

n - 4 \overline{\smash{)} -10n^2 + 26n - 8}

Explanation:

Step1: Use polynomial long division. Divide the first term of the dividend \(n^3 - 10n^2 + 26n - 8\) by the first term of the divisor \(n - 4\), which is \(n\). Multiply the divisor by \(n^2\) to get \(n^3 - 4n^2\). Subtract this from the dividend:

\[

$$\begin{align*} &(n^3 - 10n^2 + 26n - 8) - (n^3 - 4n^2)\\ =&n^3 - 10n^2 + 26n - 8 - n^3 + 4n^2\\ =& -6n^2 + 26n - 8 \end{align*}$$

\]

Step2: Now, divide the first term of \(-6n^2 + 26n - 8\) (which is \(-6n^2\)) by \(n\) (the first term of the divisor), getting \(-6n\). Multiply the divisor by \(-6n\) to get \(-6n^2 + 24n\). Subtract this from \(-6n^2 + 26n - 8\):

\[

$$\begin{align*} &(-6n^2 + 26n - 8) - (-6n^2 + 24n)\\ =& -6n^2 + 26n - 8 + 6n^2 - 24n\\ =& 2n - 8 \end{align*}$$

\]

Step3: Divide the first term of \(2n - 8\) (which is \(2n\)) by \(n\), getting \(2\). Multiply the divisor by \(2\) to get \(2n - 8\). Subtract this from \(2n - 8\):

\[
(2n - 8) - (2n - 8) = 0
\]

Step4: Combine the results from each step. The quotient is \(n^2 - 6n + 2\) and the remainder is \(0\). So, \((n^3 - 10n^2 + 26n - 8) \div (n - 4)=n^2 - 6n + 2\).

Answer:

\(n^2 - 6n + 2\)