Question

algebra ia exam review
work on all questions for credit.
i can solve one - step equations.
the equation:

• 13 + x = 11 \t 2. 5y = - 12 \t 3. \\(\frac{z}{-3} = - 6\\) \t 4. \\(\frac{5}{8} = a + \frac{1}{2}\\)

i can solve multi - step equations.
e equation:
= \\(\frac{k}{3} - 4\\) \t 6. 3x - 8 = 19

r - 6) = - 42 \t 8. 19 = 15w - 4(3w - 1)

i can solve equations with variables on both sides.
equation:

• 7 = - 3x \t 10. 7y + 13 = 5y - 3

• 1) = 3(g + 6) \t 12. - 2(5x - 10) = 5(3 - 2x) - x

Explanation:

1. Solve $-13 + x = 11$

Step1: Add 13 to both sides

$x = 11 + 13$

Step2: Calculate the sum

$x = 24$

2. Solve $5y = -12$

Step1: Divide by 5 on both sides

$y = \frac{-12}{5}$

3. Solve $\frac{z}{-3} = -6$

Step1: Multiply by -3 on both sides

$z = -6 \times (-3)$

Step2: Calculate the product

$z = 18$

4. Solve $\frac{5}{8} = a + \frac{1}{2}$

Step1: Subtract $\frac{1}{2}$ from both sides

$a = \frac{5}{8} - \frac{1}{2}$

Step2: Convert to common denominator

$a = \frac{5}{8} - \frac{4}{8}$

Step3: Subtract the fractions

$a = \frac{1}{8}$

5. Solve $=\frac{k}{3} - 4$ (Assuming equation is $0 = \frac{k}{3} - 4$)

Step1: Add 4 to both sides

$\frac{k}{3} = 4$

Step2: Multiply by 3 on both sides

$k = 12$

6. Solve $3x - 8 = 19$

Step1: Add 8 to both sides

$3x = 19 + 8$

Step2: Calculate the sum

$3x = 27$

Step3: Divide by 3 on both sides

$x = 9$

7. Solve $(r - 6) = -42$ (Assuming equation is $7(r - 6) = -42$)

Step1: Divide by 7 on both sides

$r - 6 = \frac{-42}{7}$

Step2: Simplify the right side

$r - 6 = -6$

Step3: Add 6 to both sides

$r = 0$

8. Solve $19 = 15w - 4(3w - 1)$

Step1: Expand the parentheses

$19 = 15w - 12w + 4$

Step2: Combine like terms

$19 = 3w + 4$

Step3: Subtract 4 from both sides

$15 = 3w$

Step4: Divide by 3 on both sides

$w = 5$

9. Solve $7 = -3x$ (Assuming equation is $x + 7 = -3x$)

Step1: Add $3x$ to both sides

$4x + 7 = 0$

Step2: Subtract 7 from both sides

$4x = -7$

Step3: Divide by 4 on both sides

$x = -\frac{7}{4}$

10. Solve $7y + 13 = 5y - 3$

Step1: Subtract $5y$ from both sides

$2y + 13 = -3$

Step2: Subtract 13 from both sides

$2y = -16$

Step3: Divide by 2 on both sides

$y = -8$

11. Solve $(g - 1) = 3(g + 6)$ (Assuming equation is $2(g - 1) = 3(g + 6)$)

Step1: Expand both parentheses

$2g - 2 = 3g + 18$

Step2: Subtract $2g$ from both sides

$-2 = g + 18$

Step3: Subtract 18 from both sides

$g = -20$

12. Solve $-2(5x - 10) = 5(3 - 2x) - x$

Step1: Expand both parentheses

$-10x + 20 = 15 - 10x - x$

Step2: Combine like terms

$-10x + 20 = 15 - 11x$

Step3: Add $11x$ to both sides

$x + 20 = 15$

Step4: Subtract 20 from both sides

$x = -5$

Answer:

1. $x=24$
2. $y=-\frac{12}{5}$
3. $z=18$
4. $a=\frac{1}{8}$
5. $k=12$
6. $x=9$
7. $r=0$
8. $w=5$
9. $x=-\frac{7}{4}$
10. $y=-8$
11. $g=-20$
12. $x=-5$

Note: For questions 5,7,9,11, assumptions were made to complete the incomplete equations based on standard algebra review formatting. If the original equations differ, adjust the steps accordingly.