QUESTION IMAGE
Question
algebra 1
week 6 solving practice
solve each equation.
- $8 - 6v=5v - 3$
- $5n - 6 = 6n+1$
- $5x=x - 6x$
- $2k + 7k=4 + 4k-3 - 1$
- $a + 2=14 + 3a$
- $-3x=x + 8$
- $6b - 6=8(b + 1)$
- $39 + 2a=7 + 8(4 + 8a)$
- $-5 - p=-2(p + 3)$
- $-39 + 6x=7(6 + 4x)+5x$
- $4 + 5a=4(1 - 8a)$
- $-5p + 3=-2(p + 6)$
- $-v + v=4$
- $4n - 7 - 4n=0$
- $p - 8 - p=-6$
- $-5p + 5p=-2$
- $0=-2v+2v$
- $8 - 7r + 7r=13$
Response
- For the equation \(8 - 6v=5v - 3\):
- Step 1: Add \(6v\) to both sides
- The goal is to get all the variable - terms on one side. \(8-6v + 6v=5v-3 + 6v\), which simplifies to \(8 = 11v-3\).
- Step 2: Add 3 to both sides
- To isolate the term with the variable, \(8 + 3=11v-3 + 3\), resulting in \(11 = 11v\).
- Step 3: Divide both sides by 11
- \(\frac{11}{11}=\frac{11v}{11}\), so \(v = 1\).
- For the equation \(5n-6 = 6n + 1\):
- Step 1: Subtract \(5n\) from both sides
- \(5n-6-5n=6n + 1-5n\), giving \(-6=n + 1\).
- Step 2: Subtract 1 from both sides
- \(-6-1=n + 1-1\), so \(n=-7\).
- For the equation \(5x=x - 6x\):
- Step 1: Simplify the right - hand side
- Combine like terms on the right - hand side: \(x-6x=-5x\), so the equation becomes \(5x=-5x\).
- Step 2: Add \(5x\) to both sides
- \(5x + 5x=-5x+5x\), which gives \(10x = 0\).
- Step 3: Divide both sides by 10
- \(\frac{10x}{10}=\frac{0}{10}\), so \(x = 0\).
- For the equation \(2k + 7k=4 + 4k-3-1\):
- Step 1: Simplify both sides
- Combine like terms on the left - hand side: \(2k + 7k = 9k\). Combine like terms on the right - hand side: \(4 + 4k-3-1=4k+(4 - 3-1)=4k\). So the equation is \(9k=4k\).
- Step 2: Subtract \(4k\) from both sides
- \(9k-4k=4k-4k\), resulting in \(5k = 0\).
- Step 3: Divide both sides by 5
- \(\frac{5k}{5}=\frac{0}{5}\), so \(k = 0\).
- For the equation \(a + 2=14+3a\):
- Step 1: Subtract \(a\) from both sides
- \(a + 2-a=14+3a-a\), giving \(2=14 + 2a\).
- Step 2: Subtract 14 from both sides
- \(2-14=14 + 2a-14\), so \(-12 = 2a\).
- Step 3: Divide both sides by 2
- \(\frac{-12}{2}=\frac{2a}{2}\), so \(a=-6\).
- For the equation \(-3x=x + 8\):
- Step 1: Subtract \(x\) from both sides
- \(-3x-x=x + 8-x\), resulting in \(-4x=8\).
- Step 2: Divide both sides by \(-4\)
- \(\frac{-4x}{-4}=\frac{8}{-4}\), so \(x=-2\).
- For the equation \(6b-6 = 8(b + 1)\):
- Step 1: Expand the right - hand side
- Using the distributive property \(8(b + 1)=8b+8\), so the equation is \(6b-6=8b + 8\).
- Step 2: Subtract \(6b\) from both sides
- \(6b-6-6b=8b + 8-6b\), giving \(-6=2b + 8\).
- Step 3: Subtract 8 from both sides
- \(-6-8=2b + 8-8\), so \(-14 = 2b\).
- Step 4: Divide both sides by 2
- \(\frac{-14}{2}=\frac{2b}{2}\), so \(b=-7\).
- For the equation \(39 + 2a=7+8(4 + 8a)\):
- Step 1: Expand the right - hand side
- Using the distributive property \(8(4 + 8a)=32+64a\), so the equation is \(39 + 2a=7+32+64a\).
- Step 2: Simplify the right - hand side
- Combine like terms on the right - hand side: \(7+32 = 39\), so \(39 + 2a=39+64a\).
- Step 3: Subtract \(2a\) from both sides
- \(39 + 2a-2a=39+64a-2a\), giving \(39=39 + 62a\).
- Step 4: Subtract 39 from both sides
- \(39-39=39 + 62a-39\), so \(0 = 62a\).
- Step 5: Divide both sides by 62
- \(\frac{0}{62}=\frac{62a}{62}\), so \(a = 0\).
- For the equation \(-5-p=-2(p + 3)\):
- Step 1: Expand the right - hand side
- Using the distributive property \(-2(p + 3)=-2p-6\), so the equation is \(-5-p=-2p-6\).
- Step 2: Add \(2p\) to both sides
- \(-5-p+2p=-2p-6+2p\), giving \(-5 + p=-6\).
- Step 3: Add 5 to both sides
- \(-5 + p+5=-6+5\), so \(p=-1\).
- For the equation \(-39 + 6x=7(6 + 4x)+5x\):
- Step 1: Expand the right - hand side
- Usi…
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