Question

aluminum has a density of 2.71 g/cm³. a sample of aluminum has a volume of 20.5 cm³. a sample of an unknown material has a volume of 9.83 cm³ and the same mass as the sample of aluminum. what is the density of the unknown material? density:

Explanation:

Step1: Calculate mass of aluminum sample

Use formula $m =
ho V$. Given $
ho_{aluminum}=2.71\ g/cm^{3}$ and $V_{aluminum}=20.5\ cm^{3}$, so $m = 2.71\times20.5$.
$m=2.71\times20.5 = 55.555\ g$

Step2: Calculate density of unknown material

The unknown material has mass $m = 55.555\ g$ and volume $V = 9.83\ cm^{3}$. Use density formula $
ho=\frac{m}{V}$.
$
ho=\frac{55.555}{9.83}\approx5.65\ g/cm^{3}$

Answer:

$5.65\ g/cm^{3}$