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9. at an amusement park, 360 visitors rode the roller coaster in 3 hour…

Question

  1. at an amusement park, 360 visitors rode the roller coaster in 3 hours. write and solve a proportion to find the number of visitors at this rate who will ride the roller coaster in 7 hours.
  2. reason abstractly use the table to write a proportion relating the weights on two planets. then find the missing weight. round to the nearest tenth.

a. earth: 90 pounds; venus: ____ pounds
b. mercury: 55 pounds; earth: ____ pounds
c. jupiter: 350 pounds; uranus: ____ pounds
d. venus: 115 pounds; mercury: ____ pounds
(table: weights on different planets, earth weight = 120 pounds; mercury: 45.6, venus: 109.2, uranus: 96, jupiter: 304.8)

  1. justify conclusions a powdered drink mix calls for a ratio of powder to water of 1:8. if there are 32 cups of powder, how many total cups of water are needed? explain your reasoning.
  2. solve each equation: ( \frac{2}{3} = \frac{18}{x + 5} )
  3. ( \frac{x - 4}{10} = \frac{7}{5} )
  4. ( \frac{4.5}{17 - x} = \frac{3}{8} )
  5. justify conclusions a rectangle has an area of 36 square units. as the length and the width change, what do you know about their product? is the length proportional to the width? justify your reasoning. (table: rectangle, length, width; a: 3,12; b:6,6; c:9,4)

chapter 1 ratios and proportional reasoning

Explanation:

Response
Problem 9

Step1: Define the proportion

Let \( x \) be the number of visitors in 7 hours. The rate is constant, so \(\frac{360}{3}=\frac{x}{7}\).

Step2: Solve for \( x \)

Cross - multiply: \( 3x = 360\times7 \). Then \( 3x=2520 \), and \( x=\frac{2520}{3}=840 \).

Step1: Find the ratio of Venus to Earth weight

From the table, when Earth weight is 120 pounds, Venus weight is 109.2 pounds. The ratio \( r=\frac{109.2}{120} \).

Step2: Calculate Venus weight for 90 Earth pounds

Let \( x \) be the Venus weight. Then \(\frac{x}{90}=\frac{109.2}{120}\). Cross - multiply: \( 120x = 90\times109.2 \). \( 120x = 9828 \), \( x=\frac{9828}{120}=81.9 \).

Step1: Find the ratio of Mercury to Earth weight

From the table, when Earth weight is 120 pounds, Mercury weight is 45.6 pounds. The ratio \( r = \frac{45.6}{120}\).

Step2: Calculate Earth weight for 55 Mercury pounds

Let \( x \) be the Earth weight. Then \(\frac{55}{x}=\frac{45.6}{120}\). Cross - multiply: \( 45.6x=55\times120 \). \( 45.6x = 6600 \), \( x=\frac{6600}{45.6}\approx144.7 \).

Answer:

840

Problem 10a