Question

ance between the points j=(0, -8) and h=(8, -5) in the coordinate plane.
er to the nearest hundredth.

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $(x_1,y_1)=(0,-8)$ and $(x_2,y_2)=(8,-5)$.

Step2: Substitute values

Substitute $x_1 = 0$, $y_1=-8$, $x_2 = 8$, $y_2=-5$ into the formula: $d=\sqrt{(8 - 0)^2+(-5-(-8))^2}=\sqrt{8^2+( - 5 + 8)^2}=\sqrt{64 + 9}$.

Step3: Calculate result

$\sqrt{64 + 9}=\sqrt{73}\approx8.54$.

Answer:

$8.54$