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Question
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☑ $1,203 - d = 758
☐ $d - 1,203 = 758
☐ $d - 758 = 1,203
☐ $758 - d = 1,203
☑ $1,203 - 758 = d
2a) josie made $73.29 from a garage sale on sunday. this is $37.50 less than saturdays sales.
enter a subtraction equation that could be used to find saturdays sales $s$.
2b) which value could represent saturdays sales? choose the correct answer.
○ $35.79
○ $44.39
○ $100.79
☑ $110.79
- a number of organizations contributed a total of $4,382.40 toward a job training program. each organization contributed $365.20. the equation $365.20x = 4,382.40$ can be used to find the number of organizations $x$ that contributed to the program. which is a solution of the equation? use substitution to determine the value of $x$. choose the correct answer.
○ 12
○ 13
○ 365
○ 4,017
- chester ran $2\frac{2}{5}$ miles. altogether, chester and monica ran $6\frac{1}{5}$ miles. using the equation $m + 2\frac{2}{5} = 6\frac{1}{5}$, what is the value of $m$, the distance monica ran in miles? enter the answer.
Step1: Solve for d (top question)
We need equations that relate 1,203, 758, and d.
- $1,203 - d = 758$: Rearranged gives $d=1,203-758$, valid.
- $d - 1,203 = 758$: Rearranged gives $d=1,981$, invalid.
- $d - 758 = 1,203$: Rearranged gives $d=1,981$, invalid.
- $758 - d = 1,203$: Rearranged gives $d=-445$, invalid.
- $1,203 - 758 = d$: Directly calculates d, valid.
Step2: 2A - Set up equation for s
Sunday's sales = Saturday's sales - $37.50$
$73.29 = s - 37.50$
Rearrange to isolate s: $s = 73.29 + 37.50$
Step3: 2A - Calculate s
$s = 73.29 + 37.50 = 110.79$
Step4: 3 - Solve for x
Divide both sides by 365.20:
$x = \frac{4,382.40}{365.20}$
$x = 12$
Step5: 4 - Solve for m
Subtract $2\frac{2}{5}$ from both sides:
$m = 6\frac{1}{5} - 2\frac{2}{5}$
Convert to improper fractions:
$m = \frac{31}{5} - \frac{12}{5} = \frac{19}{5}$
Convert back to mixed number:
$m = 3\frac{4}{5}$
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- Valid equations:
- $1,203 - d = 758$
- $1,203 - 758 = d$
- 2A: $s - 37.50 = 73.29$ (or $73.29 + 37.50 = s$)
- 2B: $\$110.79$
- 3: 12
- 4: $3\frac{4}{5}$ (or $\frac{19}{5}$)