Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

area of parallelograms, trapezoids, triangles and rectangles #9 calcula…

Question

area of parallelograms, trapezoids, triangles and rectangles
#9
calculate the area:
trapezoid with top base 2in, bottom base 12in, height 7in
select the question using the arrow in the yellow box. put you blue box. if you are cor
#1 40 m² #11
#2 32 in² #12
#3 45 in² #13
#4 20 mm² #14
#5 56 cm² #15
#6 48 in² #16
#7 84 in² #17
#8 22 mm² #18
#9 #19
#10 #20

Explanation:

Step1: Recall trapezoid area formula

The area of a trapezoid is given by $\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h$, where $b_1$ and $b_2$ are the lengths of the two parallel bases, and $h$ is the height.

Step2: Substitute given values

Here, $b_1 = 2\text{in}$, $b_2 = 12\text{in}$, $h = 7\text{in}$. Substitute into the formula:
$\text{Area} = \frac{1}{2} \times (2 + 12) \times 7$

Step3: Calculate sum of bases

First compute $2 + 12 = 14$

Step4: Compute final area

$\text{Area} = \frac{1}{2} \times 14 \times 7 = 7 \times 7 = 49$

Answer:

$49\text{ in}^2$