QUESTION IMAGE
Question
assume that thermometer readings are normally distributed with a mean of 0°c and a standard deviation of 1.00°c. a thermometer is randomly selected and tested. for the case below, draw a sketch, and find the probability of the reading. (the given values are in celsius degrees.) between 1.00 and 2.25. click to view page 1 of the table. click to view page 2 of the table. draw a sketch. choose the correct graph below. (options a, b, c with images: a, b, c show normal curves with z=1.00 and z=2.25, different shaded regions.)
Part 1: Choosing the Correct Graph
To determine the correct sketch for the probability between \( z = 1.00 \) and \( z = 2.25 \) in a standard normal distribution:
- The standard normal curve is symmetric around \( z = 0 \), with the peak at \( z = 0 \).
- We want the area between \( z = 1.00 \) and \( z = 2.25 \), which is the region to the right of \( z = 1.00 \) and to the left of \( z = 2.25 \) (since both \( z \)-scores are positive, they lie to the right of the mean \( z = 0 \)).
Now, analyze the options:
- Option A: Shows a small shaded area between \( z = 1.00 \) and \( z = 2.25 \), which matches the region between two positive \( z \)-scores.
- Option B: The shaded area is only at \( z = 2.25 \) (extreme right), not between \( z = 1.00 \) and \( z = 2.25 \).
- Option C: The shaded area is to the left of \( z = 1.00 \) (or a larger region), which does not represent the area between \( z = 1.00 \) and \( z = 2.25 \).
Thus, the correct graph is Option A.
Part 2: Calculating the Probability
To find \( P(1.00 < Z < 2.25) \) for a standard normal variable \( Z \):
Recall that for a standard normal distribution, \( P(a < Z < b) = P(Z < b) - P(Z < a) \), where \( P(Z < z) \) is the cumulative probability from the left up to \( z \).
Step 1: Find \( P(Z < 2.25) \)
Using the standard normal table (z-table):
- For \( z = 2.25 \), the cumulative probability \( P(Z < 2.25) = 0.9878 \) (from z-table: row 2.2, column 0.05).
Step 2: Find \( P(Z < 1.00) \)
Using the standard normal table:
- For \( z = 1.00 \), the cumulative probability \( P(Z < 1.00) = 0.8413 \) (from z-table: row 1.0, column 0.00).
Step 3: Compute the Difference
\[
P(1.00 < Z < 2.25) = P(Z < 2.25) - P(Z < 1.00) = 0.9878 - 0.8413 = 0.1465
\]
Final Answers
- Correct graph: \(\boldsymbol{\text{Option A}}\)
- Probability: \(\boldsymbol{0.1465}\) (or 14.65%)
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Part 1: Choosing the Correct Graph
To determine the correct sketch for the probability between \( z = 1.00 \) and \( z = 2.25 \) in a standard normal distribution:
- The standard normal curve is symmetric around \( z = 0 \), with the peak at \( z = 0 \).
- We want the area between \( z = 1.00 \) and \( z = 2.25 \), which is the region to the right of \( z = 1.00 \) and to the left of \( z = 2.25 \) (since both \( z \)-scores are positive, they lie to the right of the mean \( z = 0 \)).
Now, analyze the options:
- Option A: Shows a small shaded area between \( z = 1.00 \) and \( z = 2.25 \), which matches the region between two positive \( z \)-scores.
- Option B: The shaded area is only at \( z = 2.25 \) (extreme right), not between \( z = 1.00 \) and \( z = 2.25 \).
- Option C: The shaded area is to the left of \( z = 1.00 \) (or a larger region), which does not represent the area between \( z = 1.00 \) and \( z = 2.25 \).
Thus, the correct graph is Option A.
Part 2: Calculating the Probability
To find \( P(1.00 < Z < 2.25) \) for a standard normal variable \( Z \):
Recall that for a standard normal distribution, \( P(a < Z < b) = P(Z < b) - P(Z < a) \), where \( P(Z < z) \) is the cumulative probability from the left up to \( z \).
Step 1: Find \( P(Z < 2.25) \)
Using the standard normal table (z-table):
- For \( z = 2.25 \), the cumulative probability \( P(Z < 2.25) = 0.9878 \) (from z-table: row 2.2, column 0.05).
Step 2: Find \( P(Z < 1.00) \)
Using the standard normal table:
- For \( z = 1.00 \), the cumulative probability \( P(Z < 1.00) = 0.8413 \) (from z-table: row 1.0, column 0.00).
Step 3: Compute the Difference
\[
P(1.00 < Z < 2.25) = P(Z < 2.25) - P(Z < 1.00) = 0.9878 - 0.8413 = 0.1465
\]
Final Answers
- Correct graph: \(\boldsymbol{\text{Option A}}\)
- Probability: \(\boldsymbol{0.1465}\) (or 14.65%)