Question

assuming the width is the shorter side of the rectangle, what is double the width of the rectangle?
46
assuming the length is the longer side of the rectangle, what is double the length of the rectangle?
78
what is the perimeter of the rectangle?

Explanation:

Step1: Recall the perimeter formula of a rectangle

The perimeter \( P \) of a rectangle is given by the formula \( P = 2\times(\text{length}+\text{width}) \), which can also be written as \( P=\text{double the length}+\text{double the width} \).

Step2: Identify the values of double the length and double the width

From the problem, double the width is 46 and double the length is 78.

Step3: Calculate the perimeter

To find the perimeter, we add double the length and double the width. So, \( P = 46 + 78 \).
\( 46+78 = 124 \)? Wait, no, wait, 46 + 78: 40+70 = 110, 6+8 = 14, 110+14 = 124? Wait, no, wait the first two boxes: the first says double the width is 46, the second double the length is 78. Then perimeter is 46 + 78 = 124? Wait, no, wait 46 + 78: 46 + 70 = 116, 116 + 8 = 124. Wait, but let's check again. The formula for perimeter of a rectangle is \( P = 2l + 2w \), where \( l \) is length and \( w \) is width. So if \( 2w = 46 \) and \( 2l = 78 \), then \( P=2l + 2w=78 + 46 = 124 \).

Answer:

124