Question

the axis of symmetry for $f(x)=7(x - 1)^2+6$ is $x =$

Explanation:

Step1: Recall vertex - form of quadratic function

The vertex - form of a quadratic function is $y = a(x - h)^2+k$, and the axis of symmetry is given by the equation $x = h$.

Step2: Identify the value of $h$

For the function $f(x)=7(x - 1)^2+6$, comparing it with $y = a(x - h)^2+k$, we have $h = 1$.

Answer:

$x = 1$