Question

a baseball diamond is a square with sides of 90 feet. what is the shortest distance, to the nearest foot, between first base and third base? 129 feet 128 feet 127 feet

Explanation:

Step1: Apply Pythagorean theorem

The distance between first and third base is the diagonal of the square. For a square with side length $s$, diagonal $d$ is given by $d = s\sqrt{2}$. Here, $s=90$ feet.
$d = 90\sqrt{2}$

Step2: Calculate numerical value

First compute $\sqrt{2} \approx 1.4142$, then multiply by 90.
$d \approx 90 \times 1.4142 = 127.278$

Step3: Round to nearest foot

Round 127.278 to the closest whole number.
$d \approx 127$

Answer:

127 feet