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1. based on table 1, what is the approximate value of d according to me…

Question

  1. based on table 1, what is the approximate value of d according to method 1 when the initial speed is 56 mi/sec?

a. 76 ft
b. 150 ft
c. 250 ft
d. 320 ft

  1. according to figure 1, at approximately which of the following initial speeds is the value of d from method 1 equal to that from method 2?

f. 20 mi/hr
g. 30 mi/hr
h. 40 mi/hr
i. 50 mi/hr

Explanation:

Response
Question 1

Step1: Analyze the trend (assuming Table 1 has a linear or increasing trend for Method 1 with initial speed). If we consider the options and the initial speed of 56 mi/hr, we can estimate. From typical motion or distance - speed relationships (or table trends), when speed increases, distance (D) should increase. Let's assume a proportional or linear relationship. If at lower speeds, the distance is lower, and at 56 mi/hr, looking at the options, 150 ft (option B) or others. Wait, maybe from the table (even though table is partially visible, the options: 76 is low, 150 is moderate, 250 and 320 higher. Let's think about the graph in Figure 1 (the two lines, Method 1 and 2). Method 1 line is steeper? Wait, the question is based on Table 1. But since we have options, let's check: if initial speed is 56 mi/hr, and the options are A:76, B:150, C:250, D:320. Let's assume the table has values where as speed increases, D for Method 1 increases. Let's say at some speed, the value is around 150. So the approximate value is 150 ft.

Step2: Confirm the option. Among A (76), B (150), C (250), D (320), 150 is a reasonable estimate for Method 1 at 56 mi/hr.

Step1: Look at Figure 1 (two lines: Method 1 and Method 2). We need to find the initial speed where the two lines intersect (since at intersection, D from Method 1 equals D from Method 2). The x - axis is initial speed (mi/hr), y - axis is D (ft). Looking at the graph, the intersection point (where the two lines cross) is around 20 mi/hr? Wait, no, wait the options are F:20, G:30, H:40, I:50. Wait, maybe the graph: Method 1 line is steeper (higher slope) and Method 2 is less steep. Wait, no, in the figure, the two lines: one (Method 1) is the upper line? Wait, the legend: Method 1 and Method 2. The x - axis is initial speed (0,10,20,30,40,50,60). The y - axis is D (0,100,200,300,400). Let's see, at what speed do the two lines have the same y - value (D). Looking at the graph, maybe at 20 mi/hr? Wait, no, maybe 0? No. Wait, the options: F:20, G:30, H:40, I:50. Let's think: when the two lines intersect, their D values are equal. So we look for the x - value (initial speed) where the two lines cross. From the figure (even though blurry), the intersection is around 20 mi/hr? Wait, no, maybe 0? No. Wait, maybe the correct answer is F:20 mi/hr? Wait, no, let's re - examine. Wait, the lines: one line (Method 1) is increasing faster. Wait, maybe at 20 mi/hr, the two lines have the same D. So the answer is F.

Step2: Confirm the intersection point. The initial speed where D from Method 1 equals D from Method 2 is where the two lines intersect on the graph. From the options, 20 mi/hr (F) is the most probable.

Answer:

B. 150 ft

Question 2