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Question
baxton townsend practice test #2
- $3x - 8 = -26$
- $2 - \frac{2}{3}x + 6 = 2$
- $\frac{x}{4} - 2 = -6$
- $-3x + 27 = 25-$
- $3x - 6 < -5x + 14$
- $-2x + 8 \geq 6x - 12$
- $-4x + 3 = 7x - 45-$
- $\frac{x}{2} + 6 \leq \frac{5}{2}x - 12$
- $-\frac{2}{5}x + 2 > 8$
- $\frac{1}{5}x - 3 < \frac{3}{5}x + 2$
- $\frac{x}{2} + 6 \leq -9$
- $\frac{2}{3}x = -\frac{6}{21}$
Step1: Solve 1: Isolate x term
$13x = -26 + 8$
$13x = -18$
Step1a: Solve for x
$x = \frac{-18}{13}$
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Step2: Solve 2: Isolate x term
$-\frac{2}{3}x = 2 - 2 - 6$
$-\frac{2}{3}x = -6$
Step2a: Solve for x
$x = -6 \times (-\frac{3}{2}) = 9$
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Step3: Solve 3: Isolate x term
$\frac{3}{4}x = -6 + 2$
$\frac{3}{4}x = -4$
Step3a: Solve for x
$x = -4 \times \frac{4}{3} = -\frac{16}{3}$
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Step4: Solve 4: Isolate x term
$-3x = -25 - 4 - 2$
$-3x = -31$
Step4a: Solve for x
$x = \frac{31}{3}$
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Step5: Solve 5: Isolate x term
$-3x + 5x < -5 + 11 + 6$
$2x < 12$
Step5a: Solve for x
$x < 6$
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Step6: Solve 6: Isolate x term
$-2x - 6x \geq -12 - 6 + 18$
$-8x \geq 0$
Step6a: Solve for x
$x \leq 0$
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Step7: Solve 7: Isolate x term
$-9x - 7x < -45 - 3 - 1$
$-16x < -49$
Step7a: Solve for x
$x > \frac{49}{16}$
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Step8: Solve 8: Isolate x term
$-\frac{x}{2} - \frac{5}{2}x \leq -12 - 8 - 6$
$-3x \leq -26$
Step8a: Solve for x
$x \geq \frac{26}{3}$
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Step9: Solve 9: Isolate x term
$-\frac{2}{5}x - 2x > 8 - 9$
$-\frac{12}{5}x > -1$
Step9a: Solve for x
$x < \frac{5}{12}$
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Step10: Solve 10: Isolate x term
$\frac{1}{5}x - \frac{3}{5}x < 2 + 3$
$-\frac{2}{5}x < 5$
Step10a: Solve for x
$x > -\frac{25}{2}$
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Step11: Solve 11: Isolate x term
$\frac{x}{2} \leq -9 - 6$
$\frac{x}{2} \leq -15$
Step11a: Solve for x
$x \leq -30$
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Step12: Solve 12: Solve for x
$x = -\frac{6}{21} \div \frac{3}{7}$
$x = -\frac{6}{21} \times \frac{7}{3} = -\frac{2}{3}$
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- $x = -\frac{18}{13}$
- $x = 9$
- $x = -\frac{16}{3}$
- $x = \frac{31}{3}$
- $x < 6$
- $x \leq 0$
- $x > \frac{49}{16}$
- $x \geq \frac{26}{3}$
- $x < \frac{5}{12}$
- $x > -\frac{25}{2}$
- $x \leq -30$
- $x = -\frac{2}{3}$