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8. if bd = bc, bd = 5x - 26, bc = 2x + 1, and ac = 43, find ab.

Question

  1. if bd = bc, bd = 5x - 26, bc = 2x + 1, and ac = 43, find ab.

Explanation:

Step1: Set up the equation based on equal - length segments

Since $\overline{BD}=\overline{BC}$, we have $5x - 26=2x + 1$.

Step2: Solve the equation for $x$

Subtract $2x$ from both sides: $5x-2x - 26=2x-2x + 1$, which simplifies to $3x-26 = 1$. Then add 26 to both sides: $3x-26 + 26=1 + 26$, so $3x=27$. Divide both sides by 3: $x=\frac{27}{3}=9$.

Step3: Find the length of $BC$

Substitute $x = 9$ into the expression for $BC$. $BC=2x + 1=2\times9+1=18 + 1=19$.

Step4: Find the length of $AB$

We know that $AC=AB + BC$. Given $AC = 43$ and $BC = 19$, then $AB=AC - BC$. So $AB=43-19 = 24$.

Answer:

24