Question

in belmont, the library is 8 miles due south of the courthouse and 15 miles due west of the community swimming pool. what is the distance between the courthouse and the community swimming pool?

square miles

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Explanation:

Step1: Identify right triangle sides

The distance from courthouse to library is 8 miles (one leg), library to pool is 15 miles (other leg).

Step2: Apply Pythagorean theorem

Let \( c = \sqrt{a^2 + b^2} = \sqrt{8^2 + 15^2} \)

Step3: Calculate the value

\( \sqrt{64 + 225} = \sqrt{289} = 17 \)

Answer:

17