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a bicycle manufacturer is studying the reliability of one of its models…

Question

a bicycle manufacturer is studying the reliability of one of its models. the study finds that the probability of a brake defect is 4 percent and the probability of both a brake defect and a chain defect is 1 percent. if the probability of a defect with the brakes or the chain is 6 percent, what is the probability of a chain defect? 1.5 percent 2 percent 2.5 percent 3 percent

Explanation:

Step1: Recall the formula for the probability of the union of two events

The formula for the probability of the union of two events \( A \) and \( B \) is \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \). Let \( A \) be the event of a brake defect and \( B \) be the event of a chain defect. We know \( P(A) = 0.04 \), \( P(A \cap B) = 0.01 \), and \( P(A \cup B) = 0.06 \). We need to find \( P(B) \).

Step2: Rearrange the formula to solve for \( P(B) \)

From \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \), we can rearrange it to \( P(B) = P(A \cup B) - P(A) + P(A \cap B) \).

Step3: Substitute the known values into the formula

Substitute \( P(A \cup B) = 0.06 \), \( P(A) = 0.04 \), and \( P(A \cap B) = 0.01 \) into the formula: \( P(B) = 0.06 - 0.04 + 0.01 \).

Step4: Calculate the value of \( P(B) \)

First, \( 0.06 - 0.04 = 0.02 \), then \( 0.02 + 0.01 = 0.03 \). So \( P(B) = 0.03 \) or 3 percent.

Answer:

3 percent