Question

a bicyclist speeds up and then maintains a constant speed. the velocity-time graph represents its motion.a. determine the displacement of the object for the first 3 seconds. indicate the direction using a + or a - sign.displacement (0-3 s) 15 mb. determine the displacement of the object for the last 3 seconds.displacement (3-6 s) 30 mc. determine the displacement of the object for the entire 6 seconds.displacement (0-6 s) m

Explanation:

Step1: Calculate 0-3s displacement

Displacement = area of triangle: $\frac{1}{2} \times 3 \times 10 = 15$ m (positive direction, +15 m)

Step2: Calculate 3-6s displacement

Displacement = area of rectangle: $10 \times (6-3) = 30$ m (positive direction, +30 m)

Step3: Calculate total 0-6s displacement

Sum the two displacements: $15 + 30 = 45$ m

Answer:

a. +15 m
b. +30 m
c. 45 m