Question

blue light waves have more energy than red light waves. which of these situations most likely produces a photoelectric effect? you may assume that the same metal is used in each situation. check all that apply. shining dim red light on a strip of metal shining bright red light on a strip of metal shining dim blue light on a strip of metal shining bright blue light on a strip of metal

Explanation:

The photoelectric effect occurs when photons with sufficient energy hit a metal surface and eject electrons. Blue - light has more energy than red - light. The intensity (bright or dim) affects the number of ejected electrons, but the energy of the ejected electrons depends on the frequency (and thus energy) of the incident light. Since blue - light has higher energy photons, shining bright or dim blue light on the metal is more likely to cause the photoelectric effect compared to red light.

Answer:

shining bright blue light on a strip of metal
shining dim blue light on a strip of metal