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Question
bonus question a scale - drawing of a rectangular parking lot is 8 inches long and 5 inches wide. the actual parking lot is 240 feet long. what is the area of the actual parking lot, in square feet? hint: area of a rectangle = l x w
Step1: Find the scale factor
The scale - drawing length is 8 inches and the actual length is 240 feet. First, convert the units to be the same. Since 1 foot = 12 inches, 240 feet = 240×12 = 2880 inches. The scale factor $k=\frac{2880}{8}=360$.
Step2: Find the actual width
The scale - drawing width is 5 inches. Multiply the scale - drawing width by the scale factor to get the actual width. The actual width $w = 5\times360=1800$ inches. Convert this to feet: $1800\div12 = 150$ feet.
Step3: Calculate the actual area
The area of a rectangle is $A = L\times W$. The actual length $L = 240$ feet and the actual width $W = 150$ feet. So $A=240\times150 = 36000$ square feet.
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36000 square feet