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in books in her library for the last second year) school a school b num…

Question

in books in her library for the last second year)

school a school b
number of students 3000 4000
number of teachers 150 160
graduation rate 90% 80%
budget per student $10,000 $10,000
% of students in sports clubs 80% 80%
number of sports medals won 9 7
sat average 1300 1050
sat range (max-min) 800 700

analla wants to know which school has higher athletic achievements relative to the sat average.

  1. analla thought of two different ways to define this quantity. identify these two definitions among the following options.

choose 2 answers:
a % of students in sports club divided by sat average
b graduation rate divided by sat average
c number of sports medals won
d number of sports medals won divided by sat average

  1. determine which school has higher athletic achievements relative to the sat average, according to the two definitions. did you get the same result for both definitions?

choose 1 answer:
a yes. according to both definitions, school a has higher athletic achievements relative to the sat average.
b yes. according to both definitions, school b has higher athletic achievements relative to the sat average.
c no. the definitions have opposite results.

Explanation:

Response
1)
Brief Explanations

To determine athletic achievements relative to SAT average, we need metrics related to athletics and divide by SAT average. Option A uses % of sports club students (athletic - related) over SAT average. Option D uses sports medals (athletic achievement) over SAT average. Graduation rate (B) and raw medals (C) don't relate to SAT average properly for this comparison.

Step1: Define the two metrics for each school.

For School A and B, let's calculate the two metrics:

Metric 1: % of sports club students / SAT average
  • School A: \( \frac{80\%}{1300} = \frac{0.8}{1300} \approx 0.000615 \)
  • School B: \( \frac{80\%}{1050} = \frac{0.8}{1050} \approx 0.000762 \)
Metric 2: Number of sports medals / SAT average
  • School A: \( \frac{9}{1300} \approx 0.00692 \)
  • School B: \( \frac{7}{1050} \approx 0.00667 \)

Step2: Compare the metrics.

For Metric 1, School B has a higher value. For Metric 2, School A has a higher value. So the results are opposite.

Answer:

A. % of students in sports club divided by SAT average, D. Number of sports medals won divided by SAT average

2)