Question

a box has 19 candies in it: 2 are peppermint, 7 are butterscotch, and 10 are taffy. (each candy falls into only one of these categories.) ira wants to select two candies to eat for dessert. the first candy will be selected at random, and then the second candy will be selected at random from the remaining candies. what is the probability that the first candy selected is butterscotch and the second candy is taffy? do not round your intermediate computations. round your final answer to three decimal places. (if necessary, consult a list of formulas.)

Explanation:

Step1: Probability first is butterscotch

$\frac{7}{19}$

Step2: Probability second is taffy

$\frac{10}{18}$

Step3: Multiply the two probabilities

$\frac{7}{19} \times \frac{10}{18} = \frac{70}{342}$

Step4: Simplify and round to 3 decimals

$\frac{70}{342} \approx 0.205$

Answer:

0.205