Question

burke middle school has an $80 budget to stock the concession stand with drinks at the spring play. each drink costs the school 75¢, but the store will discount the full order by $100. how many drinks can the school buy for the concession stand? drew wrote an inequality to solve the problem. (cost per drink)(number of drinks) - discount ≤ 80 0.75x - 100 ≤ 80 complete drew’s work to solve for x. x ≤ \boxed{}

Explanation:

Step1: Add 100 to both sides

To isolate the term with \( x \), we add 100 to both sides of the inequality \( 0.75x - 100 \leq 80 \). This gives us \( 0.75x - 100 + 100 \leq 80 + 100 \), which simplifies to \( 0.75x \leq 180 \).

Step2: Divide both sides by 0.75

To solve for \( x \), we divide both sides of the inequality \( 0.75x \leq 180 \) by 0.75. So, \( \frac{0.75x}{0.75} \leq \frac{180}{0.75} \), which simplifies to \( x \leq 240 \).

Answer:

\( x \leq \boxed{240} \)