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if burning one gram of carbohydrates yields 17,243 joules (j) of energy…

Question

if burning one gram of carbohydrates yields 17,243 joules (j) of energy and requires 829 milliliters of oxygen, this is the same as saying 20.8 joules per ml (j/ml). how much energy from carbohydrates would the stackarel use when consuming 50 milliliters of oxygen? a) 1612 j b) 1042 j c) 531 j d) 735 j

Explanation:

Step1: Identify energy - per - mL ratio

The energy per mL of oxygen when burning carbohydrates is 20.8 J/mL.

Step2: Calculate energy for 50 mL of oxygen

We use the formula $E = r\times V$, where $r$ is the energy - per - mL ratio and $V$ is the volume of oxygen. Substituting $r = 20.8$ J/mL and $V = 50$ mL, we get $E=20.8\times50 = 1040$ J (close to 1042 J due to possible rounding in the given values).

Answer:

B. 1042 J