QUESTION IMAGE
Question
- a cafeteria starts with 750 fish sticks for lunch. each meal they serve uses 6 fish sticks. at the end of the lunch there are 42 fish sticks left. let n be the number of meals served. set up and solve an equation to find the value of n.
Step1: Define the equation
The initial number of fish sticks is 750 (wait, no, wait, the problem says "starts with 750 fish sticks"? Wait, no, the OCR might have an error. Wait, looking at the image: "A cafeteria starts with 750 fish sticks for lunch. Each meal they serve uses 6 fish sticks. At the end of the lunch there are 42 fish sticks left. Let n be the number of meals. Set up and solve an equation to find the value of n." Wait, let's correct: initial = 750, each meal uses 6, so total used is 6n, remaining is 42. So equation: 750 - 6n = 42.
Step2: Solve for n
Subtract 750 from both sides: -6n = 42 - 750 = -708. Then divide both sides by -6: n = (-708)/(-6) = 118. Wait, no, wait, maybe the initial is 75? Wait, the OCR was unclear. Wait, the user's image: "A cafeteria starts with 750 fish sticks for lunch. Each meal they serve uses 6 fish sticks. At the end of the lunch there are 42 fish sticks left. Let n be the number of meals. Set up and solve an equation to find the value of n." Wait, let's re-express:
Initial amount: 750
Amount used: 6n (since each meal uses 6, n meals use 6n)
Remaining amount: 42
So equation: 750 - 6n = 42
Step3: Solve the equation
750 - 6n = 42
Subtract 750 from both sides: -6n = 42 - 750 = -708
Divide both sides by -6: n = (-708)/(-6) = 118
Wait, but maybe the initial is 75? Let's check the OCR again. The image: "A cafeteria starts with 750 fish sticks for lunch. Each meal they serve uses 6 fish sticks. At the end of the lunch there are 42 fish sticks left. Let n be the number of meals. Set up and solve an equation to find the value of n." So 750 - 6n = 42.
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n = 118