Question

calculate the number whose square root is: a. 4/9 b. 3.6

Explanation:

Step1: Recall square - root concept

If $\sqrt{x}=y$, then $x = y^{2}$.

Step2: Calculate for part a

For $y=\frac{4}{9}$, we have $x = (\frac{4}{9})^{2}=\frac{4^{2}}{9^{2}}=\frac{16}{81}$.

Step3: Calculate for part b

For $y = 3.6$, we convert $3.6=\frac{36}{10}=\frac{18}{5}$, then $x=(\frac{18}{5})^{2}=\frac{18^{2}}{5^{2}}=\frac{324}{25}=12.96$.

Answer:

a. $\frac{16}{81}$
b. $12.96$