Question

1. calculate the pressure exerted by a column of kerosene of 3400 mm. (take the density of kerosene = 800 kg/m³).
2. a water tank is 4 meters tall and has a base area of 15m². what is the pressure at the bottom of the tank when it is filled with water to a depth of 9 meters? (assume water density is 1000 kg/m³ and g = 9.81 n/kg)
3. a 100 kg diver is lowered into the ocean to a depth of 60 meters to work on a submarine. what is the pressure on the diver? (assume seawater density is 1025 kg/m³ and g = 9.81 n/kg).

Explanation:

1.

Step1: Convert height to SI unit

First, convert 3400 mm to meters. Since 1 m = 1000 mm, $h = 3400\div1000=3.4$ m.

Step2: Use pressure - depth formula

The pressure formula is $P=
ho gh$, where $
ho = 800$ kg/m³, $g = 9.81$ N/kg and $h = 3.4$ m. Then $P=800\times9.81\times3.4$.
$P = 800\times9.81\times3.4=26601.6$ Pa.

Step1: Identify relevant values

We have $
ho = 1000$ kg/m³, $g = 9.81$ N/kg and $h = 9$ m. The base - area is not needed for calculating the pressure at the bottom of the tank using the hydro - static pressure formula $P=
ho gh$.

Step2: Calculate the pressure

$P = 1000\times9.81\times9=88290$ Pa.

Step1: Identify values for the formula

We know that $
ho = 1025$ kg/m³, $g = 9.81$ N/kg and $h = 60$ m.

Step2: Use the hydro - static pressure formula

$P=
ho gh=1025\times9.81\times60$.
$P = 1025\times9.81\times60 = 603555$ Pa.

Answer:

$26601.6$ Pa

2.