Question

calculating electric potential energy
a charge of $4.5 \times 10^{-5}$ c is placed in an electric field with a strength of $2.0 \times 10^{4}\\ \frac{\text{n}}{\text{c}}$. if the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?
______ j

Explanation:

Step1: Recall electric potential energy formula

The formula for electric potential energy in a uniform electric field is $U = qEd$, where $q$ is charge, $E$ is electric field strength, and $d$ is distance.

Step2: Substitute given values

Substitute $q=4.5 \times 10^{-5}\ \text{C}$, $E=2.0 \times 10^4\ \frac{\text{N}}{\text{C}}$, $d=0.030\ \text{m}$ into the formula:
$U = (4.5 \times 10^{-5}) \times (2.0 \times 10^4) \times 0.030$

Step3: Calculate the product

First multiply the coefficients: $4.5 \times 2.0 \times 0.030 = 0.27$
Then multiply the powers of 10: $10^{-5} \times 10^4 = 10^{-1}$
Combine results: $0.27 \times 10^{-1} = 0.027$

Answer:

0.027 J