Question

1. a car that was originally worth $29,500 depreciates at a rate of $2,500 per year. find the value of the car after six years.

rate of change
2500
initial value
29500
slope intercept form
y= x+
calories burned after 30 minutes
14,500

Explanation:

Step1: Define depreciation model

Depreciation means negative rate: $y = -2500x + 29500$

Step2: Substitute x=6 into formula

$y = -2500(6) + 29500$

Step3: Calculate total depreciation

$-2500(6) = -15000$

Step4: Compute final car value

$y = -15000 + 29500$

Answer:

Slope intercept form: $y=-2500x+29500$
Value of the car after six years: $\$14500$