Question

in cats, the gene that causes ginger fur is carried on the x chromosome. the allele for ginger colour, g, is dominant to the one for black colour, g. a female cat with black fur mates with a male cat with ginger color fur.

	x^g	x^g
y	x^g y	x^g y

blank 1| determine the probability of a male offspring having black fur.

blank 2| determine the probability of a female offspring having black fur.

blank 3| determine the probability of a female offspring being carriers of the recessive gene for black fur.

enter your answer below as a decimal between 0.00 and 1.00. (0.00, 0.10)

Explanation:

Step1: Analyze male - offspring genotypes

Male offspring have genotypes \(X^{g}Y\) and \(X^{g}Y\) from the Punnett - square. The total number of male genotypes is 2, and the number of male genotypes with black fur (\(X^{g}Y\)) is 2.

Step2: Calculate male - offspring probability

The probability \(P_{male - black}=\frac{\text{Number of male black - fur genotypes}}{\text{Total number of male genotypes}}=\frac{2}{2} = 1.00\).

Step3: Analyze female - offspring genotypes

Female offspring have genotypes \(X^{G}X^{g}\) and \(X^{G}X^{g}\) from the Punnett - square. There are no female genotypes with two \(X^{g}\) alleles.

Step4: Calculate female - offspring black - fur probability

The probability \(P_{female - black}=\frac{\text{Number of female black - fur genotypes}}{\text{Total number of female genotypes}}=\frac{0}{2}=0.00\).

Step5: Analyze female - carrier genotypes

Female offspring have genotypes \(X^{G}X^{g}\) and \(X^{G}X^{g}\), which are carriers. The total number of female genotypes is 2, and the number of carrier genotypes is 2.

Step6: Calculate female - carrier probability

The probability \(P_{female - carrier}=\frac{\text{Number of female carrier genotypes}}{\text{Total number of female genotypes}}=\frac{2}{2}=1.00\).

Answer:

1.00
0.00
1.00