Question

the cell cycle can be divided into two phases, interphase and mitosis (cell division). mitosis is further subdivided into prophase, metaphase, anaphase, telophase.
a lab technician observed 200 cells from a cell line and recorded the number of cells in each phase of the cell cycle. the results are shown in the table.

number of cells observed (out of 200)

phase	number of cells observed
prophase	20
metaphase	4
anaphase	2
telophase	4

based on the data, what is the probability a randomly - chosen cell will be observed undergoing cell division?

Explanation:

Step1: Determine number of cells undergoing cell - division

The phases of mitosis (cell - division) are prophase, metaphase, anaphase, and telophase. Add the number of cells in these phases.
$20 + 4+2 + 4=30$

Step2: Calculate probability

The probability $P$ is the number of favorable outcomes (cells undergoing cell - division) divided by the total number of outcomes (total number of cells observed).
$P=\frac{30}{200}=\frac{3}{20}=0.15$

Answer:

$0.15$