Question

1. the cell to the right is placed in an isotonic solution. the solution has a 23% concentration of solutes in the solution. based on this information, what could be the percent concentration of solutes in the solution for the cell in the picture to the left? 2. the following cell is placed in an isotonic solution with a solute concentration of 17%. what could be a possible concentration of solutes in the solution if it were placed in a hypertonic solution? (with diagrams of cells and solution containers showing percentages like 12% solute, 18% h2o, etc.)

Explanation:

Question 1

Step1: Recall isotonic solution definition

In an isotonic solution, the solute concentration inside the cell is equal to the solute concentration in the solution. The right - hand cell is in an isotonic solution with a 23% solute concentration, so the solute concentration inside the right - hand cell is 23%.

Step2: Analyze the left - hand cell's water movement

Looking at the diagram, water is moving out of the left - hand cell (the arrows show water leaving the cell). This means that the solute concentration inside the left - hand cell is less than the solute concentration in the surrounding solution (compared to the right - hand cell's isotonic situation). Wait, no, actually, if water is moving out of the left cell, the solution around the left cell is hypertonic relative to the left cell, but we know the right cell is isotonic (23% solute) with its solution. Wait, maybe I misread. Wait, the question is: The cell to the right is placed in an isotonic solution (23% solute). Based on the water movement in the left cell (water moving out), what's the solute concentration of the left cell's solution? Wait, no, the left cell's internal solute concentration? Wait, in the left cell, water is moving out, so the cell's internal solute concentration is less than the surrounding solution? But the right cell is isotonic (23% solute) with its solution. Wait, maybe the left cell's surrounding solution has a different concentration. Wait, no, the question is: "Based on this information, what could be the percent concentration of solutes in the solution for the cell in the picture to the left?" Wait, maybe the left cell is in a solution where water is moving out, so the solution around the left cell is hypertonic (higher solute concentration) than the left cell. But the right cell is in an isotonic solution (23% solute). If the left cell has water moving out, its surrounding solution has a higher solute concentration than the left cell. But we need to find the solute concentration of the solution for the left cell. Wait, maybe the left cell's internal solute concentration is such that when compared to the right cell (23% solute), since water is moving out of the left cell, the left cell's internal solute concentration is less than 23%? No, wait, water moves from low solute (high water) to high solute (low water) areas. So if water is moving out of the left cell, the solution outside the left cell has a higher solute concentration than the left cell. The right cell is in an isotonic solution (23% solute), so the right cell's internal solute concentration is 23%. The left cell has water moving out, so the left cell's internal solute concentration is less than the solution's concentration around it, but we need to find the solution's concentration for the left cell. Wait, maybe the left cell's solution has a solute concentration greater than 23%? Wait, no, let's re - express: Isotonic solution: solute (cell) = solute (solution) = 23%. For the left cell, water is moving out of the cell, so solute (solution) > solute (cell). But we don't know the cell's solute concentration. Wait, maybe the diagram shows that the left cell is losing water, so the solution around it has a higher solute concentration than the right - hand solution (23%). So a possible concentration could be 25% (any value greater than 23% would work, as long as it's higher than the left cell's internal solute concentration, and since the right cell is 23% isotonic, the left cell's solution is hypertonic to the left cell, so solute concentration of left cell's solution > 23%).

St…

Step1: Recall hypertonic solution definition

A hypertonic solution has a higher solute concentration than the cell. The cell is placed in an isotonic solution with 17% solute, so the cell's internal solute concentration is 17% (because in an isotonic solution, solute (cell) = solute (solution)).

Step2: Determine hypertonic solution concentration

In a hypertonic solution, the solute concentration of the solution is greater than the solute concentration of the cell. Since the cell has a solute concentration of 17%, the solute concentration of the hypertonic solution must be greater than 17%. For example, 18% (or 19%, 20%, etc.).

Answer:

s:

1. A possible percent concentration of solutes in the solution for the left - hand cell is 25% (any value greater than 23% is acceptable).
2. A possible concentration of solutes in the hypertonic solution is 18% (any value greater than 17% is acceptable).