Question

a cement path consists of six equal - sized cement squares arranged in a row to form a rectangle. if the total area of the path is 96 square feet, what is the length in feet of the path?
___ feet

Explanation:

Step1: Find area of one square

Let the area of one square be $A_1$. Since there are 6 squares and total area $A = 96$ square - feet, then $A_1=\frac{96}{6}=16$ square - feet.

Step2: Find side - length of one square

Let the side - length of one square be $s$. Since the area of a square $A_1 = s^2$ and $A_1 = 16$ square - feet, then $s=\sqrt{16}=4$ feet.

Step3: Find the length of the path

The path is formed by 6 squares in a row. The length $L$ of the path is the sum of the side - lengths of 6 squares. So $L = 6s$. Substituting $s = 4$ feet, we get $L=6\times4 = 24$ feet.

Answer:

24