Question

challenge activity 3.5.1: dictionary basics. start create an empty dictionary named food_quantities. click here for example 1 item_name1 = input() 2 item_count1 = int(input()) 3 item_name2 = input() 4 item_count2 = int(input()) 5 item_name3 = input() 6 item_count3 = int(input()) 7 item_name4 = input() 8 item_count4 = int(input()) 9... your code goes here... 10 11 food_quantitiesitem_name1 = item_count1 12 food_quantitiesitem_name2 = item_count2 13 food_quantitiesitem_name3 = item_count3 14 food_quantitiesitem_name4 = item_count4 15 print(f\{item_name1}: {food_quantitiesitem_name1}\) 16 print(f\{item_name2}: {food_quantitiesitem_name2}\) 17 print(f\{item_name3}: {food_quantitiesitem_name3}\) 18 print(f\{item_name4}: {food_quantitiesitem_name4}\) 1 2 3 4 5 6 check next level feedback? feedback?

Explanation:

Step1: Initialize empty dictionary

food_quantities = {}

Step2: Keep existing input lines

item_name1 = input()
item_count1 = int(input())
item_name2 = input()
item_count2 = int(input())
item_name3 = input()
item_count3 = int(input())
item_name4 = input()
item_count4 = int(input())

Step3: Assign key-value pairs to dict

food_quantities[item_name1] = item_count1
food_quantities[item_name2] = item_count2
food_quantities[item_name3] = item_count3
food_quantities[item_name4] = item_count4

Step4: Keep existing print lines

print(f"{item_name1}: {food_quantities[item_name1]}")
print(f"{item_name2}: {food_quantities[item_name2]}")
print(f"{item_name3}: {food_quantities[item_name3]}")

Answer:

food_quantities = {}
item_name1 = input()
item_count1 = int(input())
item_name2 = input()
item_count2 = int(input())
item_name3 = input()
item_count3 = int(input())
item_name4 = input()
item_count4 = int(input())

food_quantities[item_name1] = item_count1
food_quantities[item_name2] = item_count2
food_quantities[item_name3] = item_count3
food_quantities[item_name4] = item_count4

print(f"{item_name1}: {food_quantities[item_name1]}")
print(f"{item_name2}: {food_quantities[item_name2]}")
print(f"{item_name3}: {food_quantities[item_name3]}")