Question

a charge of $4.5 \times 10^{-5}$ c is placed in an electric field with a strength of $2.0 \times 10^{4} \frac{\text{n}}{\text{c}}$. what is the electric force acting on the charge?
____ n

Explanation:

Step1: Recall electric force formula

The formula for electric force is $F = qE$, where $q$ is charge, $E$ is electric field strength.

Step2: Substitute given values

$q = 4.5 \times 10^{-5}\ \text{C}$, $E = 2.0 \times 10^4\ \frac{\text{N}}{\text{C}}$
$F = (4.5 \times 10^{-5}) \times (2.0 \times 10^4)$

Step3: Calculate the product

Multiply coefficients and exponents separately:
$4.5 \times 2.0 = 9.0$
$10^{-5} \times 10^4 = 10^{-1}$
$F = 9.0 \times 10^{-1} = 0.9$

Answer:

$0.9$ N