Question

2 the chart shows the estimated total attendance at amusement parks across the united states between 2003 and 2008 along with the number of injuries that took place on rides at amusement parks. a large chain of amusement parks across the united states accounted for about 416 injuries in 2007. what percentage of the annual injuries was this?

year	attendance	number of injuries
2004	300,000,000	1,637
2005	300,400,000	1,783
2006	291,700,000	1,797
2007	292,100,000	1,664
2008	291,200,000	1,523

source: national safety council research and statistics department, amusement ride injury survey, 2008 update (p.2)

options: 25%, 4%, not enough information is given, partially visible option

Explanation:

Step1: Identify 2007's total injuries

From the table, 2007's number of injuries is 1,664.

Step2: Calculate the percentage

The formula for percentage is $\frac{\text{Part}}{\text{Whole}} \times 100\%$. Here, the part is 416 (injuries from the large chain) and the whole is 1,664 (total injuries in 2007). So we calculate $\frac{416}{1664} \times 100\%$. Simplify $\frac{416}{1664}$: divide numerator and denominator by 416, we get $\frac{1}{4}$, which is 0.25. Then $0.25 \times 100\% = 25\%$.

Answer:

25%