Question

choose all the inequalities for which the solution set is $x < 2$.
a. $x - 1 < 1$
b. $x - 2 < 0$
c. $x - 3 < 1$
d. $x + 4 < 6$

Explanation:

Step1: Solve inequality A

Add 1 to both sides:
$x - 1 + 1 < 1 + 1$
$x < 2$

Step2: Solve inequality B

Add 2 to both sides:
$x - 2 + 2 < 0 + 2$
$x < 2$

Step3: Solve inequality C

Add 3 to both sides:
$x - 3 + 3 < 1 + 3$
$x < 4$

Step4: Solve inequality D

Subtract 4 from both sides:
$x + 4 - 4 < 6 - 4$
$x < 2$

Answer:

A. $x - 1 < 1$
B. $x - 2 < 0$
D. $x + 4 < 6$