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Question
in circle n, m∠onp = 48°. solve for x if mop = (4x - 48)°. if necessary, round your answer to the nearest tenth.
Step1: Identify isosceles triangle
$NO = NP$ (radii of circle $N$), so $\triangle ONP$ is isosceles, $\angle ONP = 48^\circ$, so base angles $\angle NOP = \angle NPO$
Step2: Calculate base angles
Sum of angles in triangle is $180^\circ$.
$\angle NOP = \frac{180^\circ - 48^\circ}{2} = 66^\circ$
Step3: Relate angle to arc measure
The central angle $\angle ONP$ is equal to the measure of its intercepted arc $\overset{\frown}{OP}$.
$4x - 48 = 48$
Step4: Solve for $x$
$4x = 48 + 48$
$4x = 96$
$x = \frac{96}{4} = 24.0$
Correction: The central angle is the measure of its intercepted arc. $\angle ONP$ is the central angle for $\overset{\frown}{OP}$, so $m\overset{\frown}{OP} = m\angle ONP$ is incorrect. The correct relationship: In $\triangle ONP$, $NO=NP$, so $\angle NOP=\angle NPO$. The central angle for arc $OP$ is $\angle ONP$? No, $\angle ONP$ is the central angle, so its measure equals the arc $OP$ measure. Wait, no: Arc $OP$ is the arc between $O$ and $P$, so the central angle is $\angle ONP$, so $m\overset{\frown}{OP}=m\angle ONP$ is wrong. The correct approach: The inscribed angle over arc $OP$ would be half, but $\angle ONP$ is central. Wait, no: $\triangle ONP$ has $NO=NP$, so $\angle NOP=\angle NPO$. Let $\angle NOP=\angle NPO=y$. Then $y + y + 48=180$, so $2y=132$, $y=66$. But the arc $OP$ is equal to the central angle $\angle ONP$? No, *the arc $OP$ is equal to the central angle that subtends it, which is $\angle ONP$? No, $\angle ONP$ is the angle at the center between $O$ and $P$, so yes, $m\overset{\frown}{OP}=m\angle ONP$ is wrong. The arc $OP$ is the minor arc, so its measure is equal to the central angle $\angle ONP$. Wait, the problem says $m\overset{\frown}{OP}=(4x-48)^\circ$, and $m\angle ONP=48^\circ$. That can't be. Wait, no: $\angle ONP$ is an inscribed angle? No, $N$ is the center, so $NO$ and $NP$ are radii, so $\angle ONP$ is a central angle. Therefore, $m\overset{\frown}{OP}=m\angle ONP$? No, that would mean $4x-48=48$, so $4x=96$, $x=24$. But that ignores the triangle. Wait, no, the problem says $m\angle ONP=48^\circ$, which is the central angle, so the arc $OP$ is equal to that central angle. So $4x-48=48$, so $x=24$. The triangle's base angles are irrelevant here. The mistake was thinking the arc is related to the base angles, but no: the arc is equal to its central angle.
Final correction:
Step1: Central angle equals arc measure
The central angle $\angle ONP$ subtends $\overset{\frown}{OP}$, so $m\overset{\frown}{OP}=m\angle ONP$.
$4x - 48 = 48$
Step2: Isolate the term with $x$
Add 48 to both sides.
$4x = 48 + 48$
$4x = 96$
Step3: Solve for $x$
Divide both sides by 4.
$x = \frac{96}{4} = 24.0$
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