Question

in circle $j$, $mathrm{m}overset{\frown}{hi} = 71^{circ}$. solve for $x$ if $mathrm{m}angle hji = (7x + 28)^{circ}$. if necessary, round your answer to the nearest tenth.
answer
attempt 1 out of 2
$x = $

Explanation:

Step1: Relate arc and central angle

A central angle is equal to its intercepted arc, so:
$$7x + 28 = 71$$

Step2: Isolate the term with $x$

Subtract 28 from both sides:
$$7x = 71 - 28$$
$$7x = 43$$

Step3: Solve for $x$

Divide both sides by 7:
$$x = \frac{43}{7}$$

Step4: Round to nearest tenth

Calculate the decimal and round:
$$x \approx 6.1$$

Answer:

$x \approx 6.1$