Question

complete the following statement. use the integers that are closest to the number in the middle. (square<sqrt{21}<square)

Explanation:

Step1: Find perfect - squares around 21

We know that $4^2=16$ and $5^2 = 25$.

Step2: Compare with $\sqrt{21}$

Since $16<21<25$, then $\sqrt{16}<\sqrt{21}<\sqrt{25}$, which simplifies to $4 < \sqrt{21}<5$.

Answer:

$4 < \sqrt{21}<5$