Question

complete the table.
boys\tgirls
\t10
7\t14
9\t
\t
which points are located in quadrant ii? select all that apply.
a) (2, 7)
b) (-3, 5)
c) (-1, -5)
d) (-8, 1)
determine the area of a square that has a side length of 2.5 feet.
a hiker started his climb at 36 feet above sea level. he climbs up the hill another 14 feet. what is his altitude?

Explanation:

Step1: Identify ratio from given row

The ratio of Boys to Girls is $\frac{7}{14} = \frac{1}{2}$, so Girls = $2 \times$ Boys, Boys = $\frac{\text{Girls}}{2}$.

Step2: Fill first empty Boys cell

Calculate Boys for 10 Girls: $\frac{10}{2} = 5$

Step3: Fill third empty Girls cell

Calculate Girls for 9 Boys: $2 \times 9 = 18$

Step4: Choose any valid ratio pair

For example, Boys=2, Girls=4 (follows 1:2 ratio)

Step5: Define Quadrant II coordinates

Quadrant II has $(-x, +y)$ (negative x, positive y).

Step6: Check each point

a) $(2,7)$: $(+x,+y)$ → Quadrant I; b) $(-3,5)$: $(-x,+y)$ → Quadrant II; c) $(-1,-5)$: $(-x,-y)$ → Quadrant III; d) $(-8,1)$: $(-x,+y)$ → Quadrant II

Step7: Use square area formula

Area = $\text{side length}^2$, side = 2.5 ft

Step8: Calculate square area

$2.5^2 = 6.25$

Step9: Sum initial and climbed altitude

Initial altitude = 36 ft, climbed 14 ft: $36 + 14 = 50$

Answer:

1. Completed table:

Boys	Girls
7	14
9	18
2	4

(Note: The last row can be any pair with a 1:2 ratio)

1. b) $(-3, 5)$, d) $(-8, 1)$
2. 6.25 square feet
3. 50 feet above sea level