Question

compute: val = (√i)√j
ex: if the input is 4.0 9.0, then the output is:
val = 8.0
1 import java.util.scanner;
2
3 public class mathmethods {
4 public static void main(string args) {
5 scanner scnr = new scanner(system.in);
6 double i;
7 double j;
8 double val;
9
10 i = scnr.nextdouble();
11 j = scnr.nextdouble();
12
13 / your code goes here /
14
15 system.out.printf(\val = %.1f\
\, val); // outputs val with 1 decimal place
16 }
}

Explanation:

Step1: Take square - root of i

Let the input values for \(i\) and \(j\) be read from the user. First, calculate \(\sqrt{i}\), which in Java can be done using Math.sqrt(i).

Step2: Raise to the power of square - root of j

Then raise the result of \(\sqrt{i}\) to the power of \(\sqrt{j}\). In Java, this can be done using Math.pow(Math.sqrt(i), Math.sqrt(j)).

Here is the completed Java code:

import java.util.Scanner;

public class MathMethods {
    public static void main(String[] args) {
        Scanner scnr = new Scanner(System.in);
        double i;
        double j;
        double val;

        i = scnr.nextDouble();
        j = scnr.nextDouble();

        val = Math.pow(Math.sqrt(i), Math.sqrt(j));

        System.out.printf("val = %.1f
", val);
    }
}

If you just want the mathematical calculation part without the code:
Let \(i\) and \(j\) be the input values. First, calculate \(a=\sqrt{i}\) and \(b = \sqrt{j}\), then \(val=a^{b}\).

Answer:

The code to complete the calculation in the given Java program is val = Math.pow(Math.sqrt(i), Math.sqrt(j)); and the mathematical operation is to first find the square - root of \(i\), then raise that result to the power of the square - root of \(j\).