Question

consider (8x^2 + 40x = -104).
write the equation so that
a = 1, (x^2 + square x = square)

Explanation:

Step1: Divide the equation by 8

Given the equation \(8x^{2}+40x=-104\), we divide each term by 8 to make the coefficient of \(x^{2}\) equal to 1.
\(\frac{8x^{2}}{8}+\frac{40x}{8}=\frac{-104}{8}\)

Step2: Simplify each term

Simplifying, we get \(x^{2}+5x=-13\)

Answer:

The first blank is \(5\) and the second blank is \(-13\) (so the equation is \(x^{2}+5x=-13\))