Question

consider the following expression.
8(6 + 1)(9u + 4)
select all of the true statements below.
in (9u + 4), 9u is a constant.
6 and 1 are like terms.
8 is a factor.
(9u + 4) is written as a sum of three terms.
in 9u, 9 is a coefficient.
none of these are true.

Explanation:

Step1: Evaluate statement 1

A constant has no variable. $9u$ contains variable $u$, so it is not a constant. This statement is false.

Step2: Evaluate statement 2

Like terms are constants or same-variable terms. 6 and 1 are both constants, so they are like terms. This statement is true.

Step3: Evaluate statement 3

A factor is a multiplied value. The expression is $8 \times (6+1) \times (9u+4)$, so 8 is a factor. This statement is true.

Step4: Evaluate statement 4

$(9u+4)$ has two terms: $9u$ and $4$. It is not a sum of three terms. This statement is false.

Step5: Evaluate statement 5

A coefficient is the number multiplied by a variable. In $9u$, 9 is multiplied by $u$, so 9 is a coefficient. This statement is true.

Step6: Evaluate final statement

Since some statements are true, this is false.

Answer:

B. 6 and 1 are like terms.
C. 8 is a factor.
E. In 9u, 9 is a coefficient.